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Frequently Asked Questions (FAQ)
What are the solutions to the equation (y+2)^2+8=14 ?
- The solutions to the equation (y+2)^2+8=14 are y=sqrt(6)-2,y=-sqrt(6)-2
Find the zeros of (y+2)^2+8=14
- The zeros of (y+2)^2+8=14 are y=sqrt(6)-2,y=-sqrt(6)-2