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Frequently Asked Questions (FAQ)
What are the solutions to the equation 12x^2-160x+400=0 ?
- The solutions to the equation 12x^2-160x+400=0 are x=10,x= 10/3
Find the zeros of 12x^2-160x+400=0
- The zeros of 12x^2-160x+400=0 are x=10,x= 10/3