What are the solutions to the equation (3u-5)(8+u)=0 ?

The solutions to the equation (3u-5)(8+u)=0 are u= 5/3 ,u=-8

Find the zeros of (3u-5)(8+u)=0

The zeros of (3u-5)(8+u)=0 are u= 5/3 ,u=-8

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(3 u - 5) (8 + u) = 0

u = \frac{5}{3}, u = - 8

Solution steps

(3 u - 5) (8 + u) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 u - 5 = 0 or 8 + u = 0

Solve

3 u - 5 = 0 : u = \frac{5}{3}

Solve

8 + u = 0 : u = - 8

The solutions to the quadratic equation are:

u = \frac{5}{3}, u = - 8

4 x^{4} - 13 x^{2} + 9

\frac{d}{18} + 6 = 16

(4 + 5)^{2}

x^{8} - 4 x^{4} + 4

- 60 x + 32 = 32 x - 60

What are the solutions to the equation (3u-5)(8+u)=0 ?
The solutions to the equation (3u-5)(8+u)=0 are u= 5/3 ,u=-8
Find the zeros of (3u-5)(8+u)=0
The zeros of (3u-5)(8+u)=0 are u= 5/3 ,u=-8