展开 2x(3x+1)(x-4)

解答

展开

2 x (3 x + 1) (x - 4)

6 x^{3} - 22 x^{2} - 8 x

求解步骤

2 x (3 x + 1) (x - 4)

展开

2 x (3 x + 1) (x - 4) : 2 x (3 x^{2} - 11 x - 4)

= 2 x (3 x^{2} - 11 x - 4)

使用分配律:

m (a + b + c) = ma + mb + m c

2 x (3 x^{2} - 11 x - 4) = 2 x \cdot 3 x^{2} + 2 x (- 11 x) + 2 x (- 4)

= 2 x \cdot 3 x^{2} + 2 x (- 11 x) + 2 x (- 4)

化简

2 x \cdot 3 x^{2} + 2 x (- 11 x) + 2 x (- 4) : 6 x^{3} - 22 x^{2} - 8 x

= 6 x^{3} - 22 x^{2} - 8 x

f a c t or 2 x^{2} - 2 y + 4 x y - x

f a c t or x^{2} y^{2} + x^{2} y

f a c t or 64 a^{6} - b^{6}

s im pl i f y \frac{( a ^{8} a ^{6} ) ^{\frac{1}{7}}}{a ^{2}}

f a c t or 1 - 64 a^{3} - 12 a + 48 a^{2}