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Frequently Asked Questions (FAQ)
What are the solutions to the equation 2x^2-4x+7=0 ?
- The solutions to the equation 2x^2-4x+7=0 are x=1+isqrt(5/2),x=1-isqrt(5/2)
Find the zeros of 2x^2-4x+7=0
- The zeros of 2x^2-4x+7=0 are x=1+isqrt(5/2),x=1-isqrt(5/2)