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Frequently Asked Questions (FAQ)
What are the solutions to the equation y^2+5y-4=0 ?
- The solutions to the equation y^2+5y-4=0 are y=(-5+sqrt(41))/2 ,y=(-5-sqrt(41))/2
Find the zeros of y^2+5y-4=0
- The zeros of y^2+5y-4=0 are y=(-5+sqrt(41))/2 ,y=(-5-sqrt(41))/2