What is 1+(20}{x+1}<= \frac{20)/x ?

The solution to 1+(20}{x+1}<= \frac{20)/x is -5<= x<-1\lor 0<x<= 4

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1+(20}{x+1}<= \frac{20)/x

1 + \frac{20}{x + 1} \leq \frac{20}{x}

- 5 \leq x < - 1 or 0 < x \leq 4

Solution steps

1 + \frac{20}{x + 1} \leq \frac{20}{x}

Rewrite in standard form

\frac{x ^{2} + x - 20}{x ( x + 1 )} \leq 0

Factor

\frac{x ^{2} + x - 20}{x ( x + 1 )} : \frac{( x - 4 ) ( x + 5 )}{x ( x + 1 )}

\frac{( x - 4 ) ( x + 5 )}{x ( x + 1 )} \leq 0

Identify the intervals

- 5 \leq x < - 1 or 0 < x \leq 4

(x + 7)^{2} (x + 5) > 0

x^{2} - 16 x y + 64 y^{2}

\frac{π ^{2}}{16} - \frac{π}{8}

\frac{2}{2 - i} - \frac{2}{2 + i}

\frac{1}{8}

What is 1+(20}{x+1}<= \frac{20)/x ?
The solution to 1+(20}{x+1}<= \frac{20)/x is -5<= x<-1\lor 0<x<= 4