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Frequently Asked Questions (FAQ)
What are the solutions to the equation (4x-2)^2=17 ?
- The solutions to the equation (4x-2)^2=17 are x=(sqrt(17)+2)/4 ,x=(-sqrt(17)+2)/4
Find the zeros of (4x-2)^2=17
- The zeros of (4x-2)^2=17 are x=(sqrt(17)+2)/4 ,x=(-sqrt(17)+2)/4