-0.0006t^2+0.048t-0.29=0

解

- 0.0006 t^{2} + 0.048 t - 0.29 = 0

t = \frac{0.048 - 0.001608}{0.0012}, t = \frac{0.048 + 0.001608}{0.0012}

十進法表記

t = 6.58343 \dots, t = 73.41656 \dots

解答ステップ

- 0.0006 t^{2} + 0.048 t - 0.29 = 0

解くとthe二次式

t_{1, 2} = \frac{- 0.048 \pm 0.04 8 ^{2} - 4 ( - 0.0006 ) ( - 0.29 )}{2 ( - 0.0006 )}

0.04 8^{2} - 4 (- 0.0006) (- 0.29) = 0.001608

t_{1, 2} = \frac{- 0.048 \pm 0.001608}{2 ( - 0.0006 )}

解を分離する

t_{1} = \frac{- 0.048 + 0.001608}{2 ( - 0.0006 )}, t_{2} = \frac{- 0.048 - 0.001608}{2 ( - 0.0006 )}

t = \frac{- 0.048 + 0.001608}{2 ( - 0.0006 )} : \frac{0.048 - 0.001608}{0.0012}

t = \frac{- 0.048 - 0.001608}{2 ( - 0.0006 )} : \frac{0.048 + 0.001608}{0.0012}

二次equationの解:

t = \frac{0.048 - 0.001608}{0.0012}, t = \frac{0.048 + 0.001608}{0.0012}