What are the solutions to the equation x^2+8x+32=0 ?

The solutions to the equation x^2+8x+32=0 are x=-4+4i,x=-4-4i

Find the zeros of x^2+8x+32=0

The zeros of x^2+8x+32=0 are x=-4+4i,x=-4-4i

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x^{2} + 8 x + 32 = 0

x = - 4 + 4 i, x = - 4 - 4 i

Solution steps

x^{2} + 8 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 32 : 8 i

x_{1, 2} = \frac{- 8 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 8 i}{2 \cdot 1}

x = \frac{- 8 + 8 i}{2 \cdot 1} : - 4 + 4 i

x = \frac{- 8 - 8 i}{2 \cdot 1} : - 4 - 4 i

The solutions to the quadratic equation are:

x = - 4 + 4 i, x = - 4 - 4 i

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What are the solutions to the equation x^2+8x+32=0 ?
The solutions to the equation x^2+8x+32=0 are x=-4+4i,x=-4-4i
Find the zeros of x^2+8x+32=0
The zeros of x^2+8x+32=0 are x=-4+4i,x=-4-4i