What are the solutions to the equation 9k^2=225 ?

The solutions to the equation 9k^2=225 are k=5,k=-5

Find the zeros of 9k^2=225

The zeros of 9k^2=225 are k=5,k=-5

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9 k^{2} = 225

k = 5, k = - 5

Solution steps

9 k^{2} = 225

Divide both sides by

9

k^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 25, k = - 25

25 = 5

- 25 = - 5

k = 5, k = - 5

\frac{8 - 7 i}{1 - 2 i}

\frac{y + 3}{4} = \frac{- 5}{- 1}

(- 5 x^{4} y)^{2}

∣ 6 - 7 x ∣ + 5 \geq 7

10 x y + 15 x y^{2}

What are the solutions to the equation 9k^2=225 ?
The solutions to the equation 9k^2=225 are k=5,k=-5
Find the zeros of 9k^2=225
The zeros of 9k^2=225 are k=5,k=-5