4q^2-12q+9=0

解

4 q^{2} - 12 q + 9 = 0

q = \frac{3}{2}

十進法表記

q = 1.5

解答ステップ

4 q^{2} - 12 q + 9 = 0

解くとthe二次式

q_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

q_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

q = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

q = \frac{3}{2}

二次equationの解:

q = \frac{3}{2}