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Frequently Asked Questions (FAQ)
What are the solutions to the equation 2y^2+1=6y ?
- The solutions to the equation 2y^2+1=6y are y=(3+sqrt(7))/2 ,y=(3-sqrt(7))/2
Find the zeros of 2y^2+1=6y
- The zeros of 2y^2+1=6y are y=(3+sqrt(7))/2 ,y=(3-sqrt(7))/2