3(x-4)(x-2)+(x-1)^2=0

解

3 (x - 4) (x - 2) + (x - 1)^{2} = 0

x = \frac{5}{2}

十進法表記

x = 2.5

解答ステップ

3 (x - 4) (x - 2) + (x - 1)^{2} = 0

拡張

3 (x - 4) (x - 2) + (x - 1)^{2} : 4 x^{2} - 20 x + 25

4 x^{2} - 20 x + 25 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

x = \frac{5}{2}

二次equationの解:

x = \frac{5}{2}