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受欢迎的代数 >

solvefor x,2x^2-kx+4=0

解答

x, 2 x^{2} - k x + 4 = 0

解答

x = \frac{k + k ^{2} - 32}{4}, x = \frac{k - k ^{2} - 32}{4}

求解步骤

2 x^{2} - k x + 4 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - k ) \pm ( - k ) ^{2} - 4 \cdot 2 \cdot 4}{2 \cdot 2}

化简

(- k)^{2} - 4 \cdot 2 \cdot 4 : k^{2} - 32

x_{1, 2} = \frac{- ( - k ) \pm k ^{2} - 32}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- ( - k ) + k ^{2} - 32}{2 \cdot 2}, x_{2} = \frac{- ( - k ) - k ^{2} - 32}{2 \cdot 2}

x = \frac{- ( - k ) + k ^{2} - 32}{2 \cdot 2} : \frac{k + k ^{2} - 32}{4}

x = \frac{- ( - k ) - k ^{2} - 32}{2 \cdot 2} : \frac{k - k ^{2} - 32}{4}

二次方程组的解是:

x = \frac{k + k ^{2} - 32}{4}, x = \frac{k - k ^{2} - 32}{4}

作图

流行的例子

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