(x+1)^2-(2x+3)^2=0

Lösung

(x + 1)^{2} - (2 x + 3)^{2} = 0

x = - 2, x = - \frac{4}{3}

Dezimale

x = - 2, x = - 1.33333 \dots

Schritte zur Lösung

(x + 1)^{2} - (2 x + 3)^{2} = 0

Schreibe

(x + 1)^{2} - (2 x + 3)^{2}

um:

- 3 x^{2} - 10 x - 8

- 3 x^{2} - 10 x - 8 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 3 ) ( - 8 )}{2 ( - 3 )}

(- 10)^{2} - 4 (- 3) (- 8) = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 ( - 3 )}

Trenne die Lösungen

x_{1} = \frac{- ( - 10 ) + 2}{2 ( - 3 )}, x_{2} = \frac{- ( - 10 ) - 2}{2 ( - 3 )}

x = \frac{- ( - 10 ) + 2}{2 ( - 3 )} : - 2

x = \frac{- ( - 10 ) - 2}{2 ( - 3 )} : - \frac{4}{3}

Die Lösungen für die quadratische Gleichung sind:

x = - 2, x = - \frac{4}{3}

3 x + 6 = (x + 4)^{2} - 10

12 x^{2} + 32 x - 64 = 0

8 - t^{2} = 0

0 = 3 x^{2} - 6 x + 7

1600 = 2 y^{2}