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受欢迎的代数 >

x^2+(2x+3)^2=24

解答

x^{2} + (2 x + 3)^{2} = 24

解答

x = \frac{- 6 + 111}{5}, x = - \frac{6 + 111}{5}

+1

十进制

x = 0.90713 \dots, x = - 3.30713 \dots

求解步骤

x^{2} + (2 x + 3)^{2} = 24

展开

x^{2} + (2 x + 3)^{2} : 5 x^{2} + 12 x + 9

5 x^{2} + 12 x + 9 = 24

将

24

para o lado esquerdo

5 x^{2} + 12 x - 15 = 0

使用求根公式求解

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 ( - 15 )}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 (- 15) = 2111

x_{1, 2} = \frac{- 12 \pm 2 111}{2 \cdot 5}

将解分隔开

x_{1} = \frac{- 12 + 2 111}{2 \cdot 5}, x_{2} = \frac{- 12 - 2 111}{2 \cdot 5}

x = \frac{- 12 + 2 111}{2 \cdot 5} : \frac{- 6 + 111}{5}

x = \frac{- 12 - 2 111}{2 \cdot 5} : - \frac{6 + 111}{5}

二次方程组的解是:

x = \frac{- 6 + 111}{5}, x = - \frac{6 + 111}{5}

作图

流行的例子

2 0^{2} + 7^{2} = x^{2}

solvefor t,e=e_{0}+v_{0}*t+1/2*at^2

so l v e f or t, e = e_{0} + v_{0} \cdot t + \frac{1}{2} \cdot a t^{2}

solvefor x,2x^2-5xy-3y^2=0

so l v e f or x, 2 x^{2} - 5 x y - 3 y^{2} = 0

n (x) = (x - 2)^{2} - 3

6 a^{2} + 22 a - 8 = 0