s^2-8s+12=0

解

s^{2} - 8 s + 12 = 0

s = 6, s = 2

解答ステップ

s^{2} - 8 s + 12 = 0

解くとthe二次式

s_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 12 = 4

s_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 1}

解を分離する

s_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 1}, s_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 1}

s = \frac{- ( - 8 ) + 4}{2 \cdot 1} : 6

s = \frac{- ( - 8 ) - 4}{2 \cdot 1} : 2

二次equationの解:

s = 6, s = 2