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受欢迎的代数 >

(3n-1)x^2-(5n+2)x+2=0

解答

(3 n - 1) \cdot x^{2} - (5 n + 2) \cdot x + 2 = 0

解答

x = \frac{5 n + 2 + 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}, x = \frac{5 n + 2 - 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}; n \neq = \frac{1}{3}

求解步骤

(3 n - 1) x^{2} - (5 n + 2) x + 2 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 5 n - 2 ) \pm ( - 5 n - 2 ) ^{2} - 4 ( 3 n - 1 ) \cdot 2}{2 ( 3 n - 1 )}

化简

(- 5 n - 2)^{2} - 4 (3 n - 1) \cdot 2 : 25 n^{2} - 4 n + 12

x_{1, 2} = \frac{- ( - 5 n - 2 ) \pm 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}; n \neq = \frac{1}{3}

将解分隔开

x_{1} = \frac{- ( - 5 n - 2 ) + 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}, x_{2} = \frac{- ( - 5 n - 2 ) - 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}

x = \frac{- ( - 5 n - 2 ) + 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )} : \frac{5 n + 2 + 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}

x = \frac{- ( - 5 n - 2 ) - 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )} : \frac{5 n + 2 - 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}

二次方程组的解是:

x = \frac{5 n + 2 + 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}, x = \frac{5 n + 2 - 25 n ^{2} - 4 n + 12}{2 ( 3 n - 1 )}; n \neq = \frac{1}{3}

作图

流行的例子

c^{2} - 6 = - c

3 x^{2} - 12 x - 8 = 0

y^{2} + y = - 1

- 3 x^{2} - 7 x + 9 = 0

(3x^2)/2+8x+20=0

\frac{3 x ^{2}}{2} + 8 x + 20 = 0