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受欢迎的代数 >

solvefor y,x^3+x^2y^2-4x-2y=0

解答

求解

y, x^{3} + x^{2} y^{2} - 4 x - 2 y = 0

解答

y = \frac{1 + - x ^{3} ( x ^{2} - 4 ) + 1}{x ^{2}}, y = \frac{1 - - x ^{3} ( x ^{2} - 4 ) + 1}{x ^{2}}; x \neq = 0

求解步骤

x^{3} + x^{2} y^{2} - 4 x - 2 y = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} y^{2} - 2 y + x^{3} - 4 x = 0

使用求根公式求解

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 x ^{2} ( x ^{3} - 4 x )}{2 x ^{2}}

化简

(- 2)^{2} - 4 x^{2} (x^{3} - 4 x) : 2 1 - x^{3} (x^{2} - 4)

y_{1, 2} = \frac{- ( - 2 ) \pm 2 1 - x ^{3} ( x ^{2} - 4 )}{2 x ^{2}}; x \neq = 0

将解分隔开

y_{1} = \frac{- ( - 2 ) + 2 1 - x ^{3} ( x ^{2} - 4 )}{2 x ^{2}}, y_{2} = \frac{- ( - 2 ) - 2 1 - x ^{3} ( x ^{2} - 4 )}{2 x ^{2}}

y = \frac{- ( - 2 ) + 2 1 - x ^{3} ( x ^{2} - 4 )}{2 x ^{2}} : \frac{1 + - x ^{3} ( x ^{2} - 4 ) + 1}{x ^{2}}

y = \frac{- ( - 2 ) - 2 1 - x ^{3} ( x ^{2} - 4 )}{2 x ^{2}} : \frac{1 - - x ^{3} ( x ^{2} - 4 ) + 1}{x ^{2}}

二次方程组的解是:

y = \frac{1 + - x ^{3} ( x ^{2} - 4 ) + 1}{x ^{2}}, y = \frac{1 - - x ^{3} ( x ^{2} - 4 ) + 1}{x ^{2}}; x \neq = 0

作图

流行的例子

2 x^{2} + 4 x - 39 = x^{2}

x^2-14x+4=-10x+9

x^{2} - 14 x + 4 = - 10 x + 9

x^{2} - x + 1 = 2

1/6 n^2-1/2 n-2/3 =0

\frac{1}{6} n^{2} - \frac{1}{2} n - \frac{2}{3} = 0

solvefor a,(a/2+r)^2=(a/2-r)^2+(a/2-r)^2

so l v e f or a, (\frac{a}{2} + r)^{2} = (\frac{a}{2} - r)^{2} + (\frac{a}{2} - r)^{2}