x^2+11ax+10a^2=0

解

x^{2} + 11 a x + 10 a^{2} = 0

x = - a, x = - 10 a

解答ステップ

x^{2} + 11 a x + 10 a^{2} = 0

解くとthe二次式

x_{1, 2} = \frac{- 11 a \pm ( 11 a ) ^{2} - 4 \cdot 1 \cdot 10 a ^{2}}{2 \cdot 1}

簡素化

(11 a)^{2} - 4 \cdot 1 \cdot 10 a^{2} : 9 a

x_{1, 2} = \frac{- 11 a \pm 9 a}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 11 a + 9 a}{2 \cdot 1}, x_{2} = \frac{- 11 a - 9 a}{2 \cdot 1}

x = \frac{- 11 a + 9 a}{2 \cdot 1} : - a

x = \frac{- 11 a - 9 a}{2 \cdot 1} : - 10 a

二次equationの解:

x = - a, x = - 10 a