x^2+16x-225=0

解

x^{2} + 16 x - 225 = 0

x = 9, x = - 25

解答ステップ

x^{2} + 16 x - 225 = 0

解くとthe二次式

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 225 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 225) = 34

x_{1, 2} = \frac{- 16 \pm 34}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 16 + 34}{2 \cdot 1}, x_{2} = \frac{- 16 - 34}{2 \cdot 1}

x = \frac{- 16 + 34}{2 \cdot 1} : 9

x = \frac{- 16 - 34}{2 \cdot 1} : - 25

二次equationの解:

x = 9, x = - 25