What is the answer to (2(X-1))/6+(3(X-2))/6 =2 ?

The answer to (2(X-1))/6+(3(X-2))/6 =2 is X=4

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(2(X-1))/6+(3(X-2))/6 =2

\frac{2 ( X - 1 )}{6} + \frac{3 ( X - 2 )}{6} = 2

X = 4

Solution steps

\frac{2 ( X - 1 )}{6} + \frac{3 ( X - 2 )}{6} = 2

Multiply both sides by

6

2 (X - 1) + 3 (X - 2) = 12

Expand

2 (X - 1) + 3 (X - 2) : 5 X - 8

5 X - 8 = 12

Move

8

to the right side

5 X = 20

Divide both sides by

5

X = 4

- x^{2} + 4 x = 6

p^{2} - 11 p + 28 = 0

∣ 6 - 4 x ∣ \leq 1

2 (\frac{1}{5})^{2}

(- \frac{5}{4})^{3}

What is the answer to (2(X-1))/6+(3(X-2))/6 =2 ?
The answer to (2(X-1))/6+(3(X-2))/6 =2 is X=4
Solve for X: (2(X-1))/6+(3(X-2))/6 =2
The solution is X=4