What are the solutions to the equation 2=(x-2)^2 ?

The solutions to the equation 2=(x-2)^2 are x=sqrt(2)+2,x=-sqrt(2)+2

Find the zeros of 2=(x-2)^2

The zeros of 2=(x-2)^2 are x=sqrt(2)+2,x=-sqrt(2)+2

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2 = (x - 2)^{2}

x = 2 + 2, x = - 2 + 2

Solution steps

2 = (x - 2)^{2}

Switch sides

(x - 2)^{2} = 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 2 : x = 2 + 2

Solve

x - 2 = - 2 : x = - 2 + 2

The solutions to the quadratic equation are:

x = 2 + 2, x = - 2 + 2

(1 - 4 i) (- 4 + 2 i)

m^{2} - 5 m = 150

x^{2} - 11 x + 24 \geq 0

\frac{x + 18}{x + 2} \geq 3

x (5 x - 8) - 2 (5 x - 8)

What are the solutions to the equation 2=(x-2)^2 ?
The solutions to the equation 2=(x-2)^2 are x=sqrt(2)+2,x=-sqrt(2)+2
Find the zeros of 2=(x-2)^2
The zeros of 2=(x-2)^2 are x=sqrt(2)+2,x=-sqrt(2)+2