x^2+20x-4800=0

解

x^{2} + 20 x - 4800 = 0

x = 60, x = - 80

解答ステップ

x^{2} + 20 x - 4800 = 0

解くとthe二次式

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 4800 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 4800) = 140

x_{1, 2} = \frac{- 20 \pm 140}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 20 + 140}{2 \cdot 1}, x_{2} = \frac{- 20 - 140}{2 \cdot 1}

x = \frac{- 20 + 140}{2 \cdot 1} : 60

x = \frac{- 20 - 140}{2 \cdot 1} : - 80

二次equationの解:

x = 60, x = - 80