What are the solutions to the equation y^2+4y=7 ?

The solutions to the equation y^2+4y=7 are y=-2+sqrt(11),y=-2-sqrt(11)

Find the zeros of y^2+4y=7

The zeros of y^2+4y=7 are y=-2+sqrt(11),y=-2-sqrt(11)

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y^{2} + 4 y = 7

y = - 2 + 11, y = - 2 - 11

Decimal Notation

y = 1.31662 \dots, y = - 5.31662 \dots

Solution steps

y^{2} + 4 y = 7

Move

7

to the left side

y^{2} + 4 y - 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 7) = 211

y_{1, 2} = \frac{- 4 \pm 2 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 2 11}{2 \cdot 1}, y_{2} = \frac{- 4 - 2 11}{2 \cdot 1}

y = \frac{- 4 + 2 11}{2 \cdot 1} : - 2 + 11

y = \frac{- 4 - 2 11}{2 \cdot 1} : - 2 - 11

The solutions to the quadratic equation are:

y = - 2 + 11, y = - 2 - 11

2 (x + 7) = 37

\frac{4}{3} x + 8 \geq 3 (1 - \frac{1}{3} x)

4 - (0.05 \cdot X) = (0.08 \cdot (80 - X))

4 x < 20

(- \frac{1}{x ^{2}})^{2}

What are the solutions to the equation y^2+4y=7 ?
The solutions to the equation y^2+4y=7 are y=-2+sqrt(11),y=-2-sqrt(11)
Find the zeros of y^2+4y=7
The zeros of y^2+4y=7 are y=-2+sqrt(11),y=-2-sqrt(11)