What are the solutions to the equation (x-3)(5x+2)=0 ?

The solutions to the equation (x-3)(5x+2)=0 are x=3,x=-2/5

Find the zeros of (x-3)(5x+2)=0

The zeros of (x-3)(5x+2)=0 are x=3,x=-2/5

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(x - 3) (5 x + 2) = 0

x = 3, x = - \frac{2}{5}

Solution steps

(x - 3) (5 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 5 x + 2 = 0

Solve

x - 3 = 0 : x = 3

Solve

5 x + 2 = 0 : x = - \frac{2}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{2}{5}

\frac{( 0.99 ) ^{3} - 1}{( 0.99 ) - 1}

6 t^{3} + 3 t^{4} - 2 t^{5} - t^{6}

25 w^{2} - 60 w + 36

2 (x^{2} - 8) - 4 = - 8

- 3 x - 4 (4 x - 8) = 3 (- 8 x - 1)

What are the solutions to the equation (x-3)(5x+2)=0 ?
The solutions to the equation (x-3)(5x+2)=0 are x=3,x=-2/5
Find the zeros of (x-3)(5x+2)=0
The zeros of (x-3)(5x+2)=0 are x=3,x=-2/5