What are the solutions to the equation 2x^2-2x-12=0 ?

The solutions to the equation 2x^2-2x-12=0 are x=3,x=-2

Find the zeros of 2x^2-2x-12=0

The zeros of 2x^2-2x-12=0 are x=3,x=-2

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2 x^{2} - 2 x - 12 = 0

x = 3, x = - 2

Solution steps

2 x^{2} - 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 12) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 2}

x = \frac{- ( - 2 ) + 10}{2 \cdot 2} : 3

x = \frac{- ( - 2 ) - 10}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

2 x^{2} - 9 = 3 x^{2}

x^{3} - 3 x^{2} - 10 x

3 (x + 1)^{2} - 243 = 0

(x^{2} + 8)^{2} - 36 x^{2}

\frac{3}{\frac{1}{4}}

What are the solutions to the equation 2x^2-2x-12=0 ?
The solutions to the equation 2x^2-2x-12=0 are x=3,x=-2
Find the zeros of 2x^2-2x-12=0
The zeros of 2x^2-2x-12=0 are x=3,x=-2