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Frequently Asked Questions (FAQ)
What are the solutions to the equation 4x^2+19x-22=0 ?
- The solutions to the equation 4x^2+19x-22=0 are x=(-19+sqrt(713))/8 ,x=(-19-sqrt(713))/8
Find the zeros of 4x^2+19x-22=0
- The zeros of 4x^2+19x-22=0 are x=(-19+sqrt(713))/8 ,x=(-19-sqrt(713))/8