What is 1/(x+1)+1/(x+2)>= 0 ?

The solution to 1/(x+1)+1/(x+2)>= 0 is -2 -1

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1/(x+1)+1/(x+2)>= 0

\frac{1}{x + 1} + \frac{1}{x + 2} \geq 0

- 2 < x \leq - \frac{3}{2} or x > - 1

Interval Notation

(- 2, - \frac{3}{2}] \cup (- 1, \infty)

Decimal Notation

- 2 < x \leq - 1.5 or x > - 1

Solution steps

\frac{1}{x + 1} + \frac{1}{x + 2} \geq 0

Rewrite in standard form

\frac{2 x + 3}{( x + 1 ) ( x + 2 )} \geq 0

Identify the intervals

- 2 < x \leq - \frac{3}{2} or x > - 1

- 3 < 3 x + 7 \leq 4

2^{2} + x^{2} = 5^{2}

\frac{2}{7} y + 5 = - 9

\frac{5}{6} \cdot \frac{1}{4}

\frac{a - b}{b - a}

What is 1/(x+1)+1/(x+2)>= 0 ?
The solution to 1/(x+1)+1/(x+2)>= 0 is -2<x<=-3/2 \lor x>-1