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Frequently Asked Questions (FAQ)
What are the solutions to the equation -16t^2+288=0 ?
- The solutions to the equation -16t^2+288=0 are t=3sqrt(2),t=-3sqrt(2)
Find the zeros of -16t^2+288=0
- The zeros of -16t^2+288=0 are t=3sqrt(2),t=-3sqrt(2)