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Frequently Asked Questions (FAQ)
What are the solutions to the equation 32t-0.8t^2=160 ?
- The solutions to the equation 32t-0.8t^2=160 are t=10(2-sqrt(2)),t=10(2+sqrt(2))
Find the zeros of 32t-0.8t^2=160
- The zeros of 32t-0.8t^2=160 are t=10(2-sqrt(2)),t=10(2+sqrt(2))