簡約 6.421*10^{-5}(1/(0.3048))^2

解

簡約

6.421 \cdot 1 0^{- 5} (\frac{1}{0.3048})^{2}

0.00069 \dots

解答ステップ

6.421 \cdot 1 0^{- 5} (\frac{1}{0.3048})^{2}

指数の規則を適用する:

a^{- b} = \frac{1}{a ^{b}}

= 6.421 (\frac{1}{0.3048})^{2} \frac{1}{1 0 ^{5}}

(\frac{1}{0.3048})^{2} = \frac{1}{0.304 8 ^{2}}

= 6.421 \cdot \frac{1}{1 0 ^{5}} \cdot \frac{1}{0.304 8 ^{2}}

分数を乗じる:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= 6.421 \cdot \frac{1 \cdot 1}{1 0 ^{5} \cdot 0.304 8 ^{2}}

\frac{1 \cdot 1}{1 0 ^{5} \cdot 0.304 8 ^{2}} = 0.00010 \dots

= 0.00010 \dots \cdot 6.421

数を乗じる:

6.421 \cdot 0.00010 \dots = 0.00069 \dots

= 0.00069 \dots