展开 (8x+6)(8x-6)'

解答

展开

(8 x + 6) (8 x - 6)^{'}

8 x (8 x - 6)' + 6 (8 x - 6)'

求解步骤

(8 x + 6) (8 x - 6)^{'}

使用分配律:

a (b + c) = ab + a c

a = (8 x - 6)^{'}, b = 8 x, c = 6

= (8 x - 6)^{^{'}} 8 x + (8 x - 6)^{^{'}} 6

= 8 x (8 x - 6)^{^{'}} + 6 (8 x - 6)^{^{'}}

e x p an d \frac{( p + 2 ) 2 + p x ^{5}}{10}

e x p an d e^{t} \cdot u (t - 8)

e x p an d \frac{x - 8}{( x + 8 ) ( x + 6 )}

e x p an d (s - e) (s - 2) (s - 5)

e x p an d \frac{x}{( x - 2 ) ( x - 3 ) ( x - 6 )}