展开 ((g+Vsin(θ)k)x)/(kVcos(θ))

解答

展开

\frac{( g + V sin ( θ ) k ) x}{kV cos ( θ )}

\frac{gx}{kV cos ( θ )} + \frac{x sin ( θ )}{cos ( θ )}

求解步骤

\frac{( g + V sin ( θ ) k ) x}{kV cos ( θ )}

乘开

(g + V sin (θ) k) x : gx + kV x sin (θ)

= \frac{gx + kV x sin ( θ )}{kV cos ( θ )}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{gx + kV x sin ( θ )}{kV cos ( θ )} = \frac{gx}{kV cos ( θ )} + \frac{kV x sin ( θ )}{kV cos ( θ )}

= \frac{gx}{kV cos ( θ )} + \frac{kV x sin ( θ )}{kV cos ( θ )}

消掉

\frac{kV x sin ( θ )}{kV cos ( θ )} : \frac{x sin ( θ )}{cos ( θ )}

= \frac{gx}{kV cos ( θ )} + \frac{x sin ( θ )}{cos ( θ )}

e x p an d \frac{5 s + 2}{( s + 1 ) ( s + 2 ) ^{2}}

s im pl i f y \frac{0.01}{s ( 0.04 s ^{3} + 0.18 s ^{2} + 0.2 s )}

e x p an d (x^{3} + b + 1)^{3} \cdot x^{2}

e x p an d \frac{( 2 p + 6 ) p}{2 p + 3}

e x p an d n (3 n)!