What is expand (-2(0)+9)/(sqrt(-(0)^2+9)) ?

The solution to expand (-2(0)+9)/(sqrt(-(0)^2+9)) is 3

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expand (-2(0)+9)/(sqrt(-(0)^2+9))

expand

\frac{- 2 ( 0 ) + 9}{- ( 0 ) ^{2} + 9}

3

Solution steps

\frac{- 2 ( 0 ) + 9}{- 0 ^{2} + 9}

Apply rule

0^{a} = 0

0^{2} = 0

= \frac{- 2 \cdot 0 + 9}{- 0 + 9}

- 2 \cdot 0 + 9 = 9

= \frac{9}{- 0 + 9}

Add/Subtract the numbers:

- 0 + 9 = 9

= \frac{9}{9}

Apply radical rule:

n a = a^{\frac{1}{n}}

9 = 9^{\frac{1}{2}}

= \frac{9}{9 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{9 ^{1}}{9 ^{\frac{1}{2}}} = 9^{1 - \frac{1}{2}}

= 9^{1 - \frac{1}{2}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= 9^{\frac{1}{2}}

Apply radical rule:

a^{\frac{1}{n}} = n a

9^{\frac{1}{2}} = 9

= 9

Factor the number:

9 = 3^{2}

= 3^{2}

Apply radical rule:

n a^{n} = a

3^{2} = 3

= 3

e x p an d dd x (e^{x^{4}} + ln (5) (π))

e x p an d \frac{2}{( s + 1 ) ( s ^{2} + 4 )}

e x p an d 0.5 (37.622 + 16 e^{1.5 x})

e x p an d v a l u es (x + 1) (x - 2) (x - 4)

e x p an d d i recc i o n (1, - 1)

What is expand (-2(0)+9)/(sqrt(-(0)^2+9)) ?
The solution to expand (-2(0)+9)/(sqrt(-(0)^2+9)) is 3