展開する (3y^{1/3}= 1/2 x^2+C) 1/3

解

展開する

(3 y^{\frac{1}{3}} = \frac{1}{2} x^{2} + C) \frac{1}{3}

y^{\frac{1}{3}} = \frac{x ^{2}}{2} + \frac{C}{3}

解答ステップ

(3 y^{\frac{1}{3}} = \frac{1}{2} x^{2} + C) \frac{1}{3}

= \frac{1}{3} (3 \cdot \frac{1}{2} = x^{2} y^{\frac{1}{3}} + C)

分配法則を適用する:

a (b + c) = ab + a c

a = \frac{1}{3}, b = 3 y^{\frac{1}{3}} = \frac{1}{2} x^{2}, c = C

\frac{1}{3} \cdot 3 y^{\frac{1}{3}} = \frac{1}{2} x^{2} + \frac{1}{3} C

3 \cdot \frac{1}{3} y^{\frac{1}{3}} = \frac{1}{2} x^{2} + \frac{1}{3} C

簡素化

3 \cdot \frac{1}{3} y^{\frac{1}{3}} = \frac{1}{2} x^{2} + \frac{1}{3} C : y^{\frac{1}{3}} = \frac{x ^{2}}{2} + \frac{C}{3}

y^{\frac{1}{3}} = \frac{x ^{2}}{2} + \frac{C}{3}