(d^2)/(dt^2)(({v}(t))(2t^2+4t+12))

Lösung

\frac{d ^{2}}{d t ^{2}} ((v (t)) (2 t^{2} + 4 t + 12))

\frac{d ^{2}}{d t ^{2}} (v (t)) (2 t^{2} + 4 t + 12) + 2 (4 t + 4) \frac{d}{d t} (v (t)) + 4 v (t)

Schritte zur Lösung

\frac{d ^{2}}{d t ^{2}} ((v (t)) (2 t^{2} + 4 t + 12))

\frac{d}{d t} (v (t) (2 t^{2} + 4 t + 12)) = \frac{d}{d t} (v (t)) (2 t^{2} + 4 t + 12) + (4 t + 4) v (t)

= \frac{d}{d t} (\frac{d}{d t} (v (t)) (2 t^{2} + 4 t + 12) + (4 t + 4) v (t))

\frac{d}{d t} (\frac{d}{d t} (v (t)) (2 t^{2} + 4 t + 12) + (4 t + 4) v (t)) = \frac{d ^{2}}{d t ^{2}} (v (t)) (2 t^{2} + 4 t + 12) + 2 (4 t + 4) \frac{d}{d t} (v (t)) + 4 v (t)

= \frac{d ^{2}}{d t ^{2}} (v (t)) (2 t^{2} + 4 t + 12) + 2 (4 t + 4) \frac{d}{d t} (v (t)) + 4 v (t)

e x p an d \frac{k ( s + 20 )}{s ( s + 2 ) \cdot ( s + 3 )}

s im pl i f y (200 g) (\frac{4.182 J}{( g ^{\circ} C )}) (36. 9^{\circ} C - 23. 8^{\circ} C)

e x p an d \frac{( - x ^{2} + 12 x - 27 )}{( - x + 6 ) ^{2}}

\frac{d}{d t} ((z (t)) ln (1 + t + (1 + t)^{2}))

e x p an d \frac{g + k}{( 1 + g ( g + k ) )}