erweitern e^{t+2}U(t-3)

Lösung

erweitern

e^{t + 2} U (t - 3)

e^{t + 2} t U - 3 e^{t + 2} U

Schritte zur Lösung

e^{t + 2} U (t - 3)

Wende das Distributivgesetz an:

a (b - c) = ab - a c

a = e^{t + 2} U, b = t, c = 3

= e^{t + 2} U t - e^{t + 2} U \cdot 3

= e^{t + 2} t U - 3 e^{t + 2} U

e x p an d (\frac{- 28}{4} bi g)^{2} (4 - 28) 2

\frac{d}{d y} ((x) ((5 x + 2 y)^{8}))

e x p an d (2 i) (3 i^{2}) (5)

e x p an d \frac{x ^{4} - x ^{3} - 13 x ^{2} + 2 x + 6}{( x + 3 ) ( x + 4 )}

e x p an d \frac{( ( 2 p + q ) ^{3} - ( q - 2 p ) ^{3} )}{2 p}