zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

展开 ((6-y)/2)^2

解答

展开

(\frac{6 - y}{2})^{2}

解答

\frac{y ^{2}}{4} - 3 y + 9

求解步骤

(\frac{6 - y}{2})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 6 - y ) ^{2}}{2 ^{2}}

(6 - y)^{2} = 36 - 12 y + y^{2}

= \frac{36 - 12 y + y ^{2}}{2 ^{2}}

2^{2} = 4

= \frac{36 - 12 y + y ^{2}}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{36 - 12 y + y ^{2}}{4} = \frac{36}{4} - \frac{12 y}{4} + \frac{y ^{2}}{4}

= \frac{36}{4} - \frac{12 y}{4} + \frac{y ^{2}}{4}

数字相除:

\frac{36}{4} = 9

= 9 - \frac{12 y}{4} + \frac{y ^{2}}{4}

数字相除:

\frac{12}{4} = 3

= 9 - 3 y + \frac{y ^{2}}{4}

改写为标准形式

= \frac{y ^{2}}{4} - 3 y + 9

流行的例子

展开 ((4y^2-7y-12))/(y(y+2)(y-3))

e x p an d \frac{( 4 y ^{2} - 7 y - 12 )}{y ( y + 2 ) ( y - 3 )}

展开 (p+1+r(t+1))/(1+r)

e x p an d \frac{p + 1 + r ( t + 1 )}{1 + r}

展开 (-(W)(L+x)^2)/2+(2LWx)

e x p an d \frac{- ( W ) ( L + x ) ^{2}}{2} + (2 L W x)

展开 16/3-8/3

e x p an d \frac{16}{3} - \frac{8}{3}

展开 (x^3y^4+x)dx+(x^4y^3+y)dy

e x p an d (x^{3} y^{4} + x) d x + (x^{4} y^{3} + y) d y