展开 dx(sec(2x)+tan(3x))

解答

展开

d x (sec (2 x) + tan (3 x))

sec (2 x) d x + tan (3 x) d x

求解步骤

d x (sec (2 x) + tan (3 x))

使用分配律:

a (b + c) = ab + a c

a = d x, b = sec (2 x), c = tan (3 x)

= d x sec (2 x) + d x tan (3 x)

= sec (2 x) d x + tan (3 x) d x

e x p an d lo g_{5 (3 x - 1)} (2)

e x p an d cot (\frac{1}{2} (x + y)) cot (\frac{1}{2} (x - y))

e x p an d (1 + e^{2 y}) (e^{y} - \frac{e ^{2 y}}{2})

e x p an d 8 \cdot \frac{d}{d t} ((- 9 t - 6) e^{- 3 t} + (4 t + 12) e^{- 5 t})

e x p an d \frac{5 ( x - 1 )}{6}