erweitern ((y+1)^2)/9

Lösung

erweitern

\frac{( y + 1 ) ^{2}}{9}

\frac{y ^{2}}{9} + \frac{2 y}{9} + \frac{1}{9}

Schritte zur Lösung

\frac{( y + 1 ) ^{2}}{9}

(y + 1)^{2} = y^{2} + 2 y + 1

= \frac{y ^{2} + 2 y + 1}{9}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{y ^{2} + 2 y + 1}{9} = \frac{y ^{2}}{9} + \frac{2 y}{9} + \frac{1}{9}

= \frac{y ^{2}}{9} + \frac{2 y}{9} + \frac{1}{9}

e x p an d \frac{7 x + 116}{( x - 4 ) ^{2} ( x + 5 )}

e x p an d \frac{7 x ^{3} + x ^{2} + 49 x + 1}{( x ^{2} + 1 ) ( x ^{2} + 7 )}

e x p an d \frac{3 x ^{2} + 3 x + 7}{( x - 2 ) ^{2} ( x ^{2} + 1 )}

e x p an d 19600 (- \frac{512}{3} + 432 π)

e x p an d \frac{2 x}{( r + 1 ) ( r - 1 )}