展开 argument(1+i)

解答

展开

a r gu m e n t (1 + i)

e amn r gu t + e amni r gu t

求解步骤

a r gu m e n t (1 + i)

= e amn r gu t (1 + i)

使用分配律:

a (b + c) = ab + a c

a = a r gu m e n t, b = 1, c = i

= a r gu m e n t \cdot 1 + a r gu m e n t i

= 1 e amn r gu t + e amni r gu t

乘以:

1 e = e

= e amn r gu t + e amni r gu t

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