解答
展开 (2(4,1,5)+(2,−3,1))⋅((4,1,5)−3(2,−3,1))
解答
2(4⋅1⋅5,,)(4⋅1⋅5,,)−2⋅3⋅2(4⋅1⋅5,,),2⋅3⋅3⋅1⋅(4⋅1⋅5,,),2(4⋅1⋅5,,),−3⋅1⋅(4⋅1⋅5,,),−3⋅2,2,3⋅2,3⋅1,3⋅3⋅1,2,3⋅1,3⋅1,
求解步骤
(2(4,1,5)+(2,−3,1))((4,1,5)−3(2,−3,1))
=(2(4⋅1⋅5,,)+(2,−3⋅1,))((4⋅1⋅5,,)−3(2,−3⋅1,))
乘开 (2(4,1,5)+(2,−3,1))((4,1,5)−3(2,−3,1)):2(4⋅1⋅5,,)(4⋅1⋅5,,)−2⋅3(4⋅1⋅5,,)(2,−3⋅1,)+(2,−3⋅1,)(4⋅1⋅5,,)−3(2,−3⋅1,)(2,−3⋅1,)
=2(4⋅1⋅5,,)(4⋅1⋅5,,)−2⋅3(4⋅1⋅5,,)(2,−3⋅1,)+(2,−3⋅1,)(4⋅1⋅5,,)−3(2,−3⋅1,)(2,−3⋅1,)
乘开 −2⋅3(4⋅1⋅5,,)(2,−3⋅1,):−2⋅3⋅2(4⋅1⋅5,,),2⋅3⋅3⋅1⋅(4⋅1⋅5,,),
=2(4⋅1⋅5,,)(4⋅1⋅5,,)−2⋅3⋅2(4⋅1⋅5,,),2⋅3⋅3⋅1⋅(4⋅1⋅5,,),(2,−3⋅1,)(4⋅1⋅5,,)−3(2,−3⋅1,)(2,−3⋅1,)
乘开 (4⋅1⋅5,,)(2,−3⋅1,):2(4⋅1⋅5,,),−3⋅1⋅(4⋅1⋅5,,),
=2(4⋅1⋅5,,)(4⋅1⋅5,,)−2⋅3⋅2(4⋅1⋅5,,),2⋅3⋅3⋅1⋅(4⋅1⋅5,,),2(4⋅1⋅5,,),−3⋅1⋅(4⋅1⋅5,,),−3(2,−3⋅1,)(2,−3⋅1,)
乘开 −3(2,−3⋅1,)(2,−3⋅1,):−3⋅2,2,3⋅2,3⋅1,3⋅3⋅1,2,3⋅1,3⋅1,
=2(4⋅1⋅5,,)(4⋅1⋅5,,)−2⋅3⋅2(4⋅1⋅5,,),2⋅3⋅3⋅1⋅(4⋅1⋅5,,),2(4⋅1⋅5,,),−3⋅1⋅(4⋅1⋅5,,),−3⋅2,2,3⋅2,3⋅1,3⋅3⋅1,2,3⋅1,3⋅1,