erweitern cos(x+y)(1+y'(x))

Lösung

erweitern

cos (x + y) (1 + y^{'} (x))

cos (x + y) + cos (x + y) y' (x)

Schritte zur Lösung

cos (x + y) (1 + y^{'} (x))

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = cos (x + y), b = 1, c = y^{'} (x)

= cos (x + y) \cdot 1 + cos (x + y) y^{^{'}} (x)

= 1 \cdot cos (x + y) + cos (x + y) y^{^{'}} (x)

Multipliziere:

1 \cdot cos (x + y) = cos (x + y)

= cos (x + y) + cos (x + y) y^{^{'}} (x)

e x p an d (2 z - 6 w (z) = 0,) (- z + 2 w (z) = - 8)

e x p an d \frac{( 49 s ^{2} + 2 ( 7 s + 1 ) )}{s ^{3}}

e x p an d \frac{5}{( s + 3 ) ^{2} ( s + 1 )}

e x p an d f (3 x^{2} - 36 x) d x

e x p an d \frac{q}{( x - a ) ^{2} ( x - b ) ^{2} ( x - c ) ^{2}}