erweitern ((2x^4)/(3x))^3

Lösung

erweitern

(\frac{2 x ^{4}}{3 x})^{3}

\frac{8 x ^{9}}{27}

Schritte zur Lösung

(\frac{2 x ^{4}}{3 x})^{3}

\frac{2 x ^{4}}{3 x} = \frac{2 x ^{3}}{3}

= (\frac{2 x ^{3}}{3})^{3}

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x ^{3} ) ^{3}}{3 ^{3}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x^{3})^{3} = 2^{3} (x^{3})^{3}

= \frac{2 ^{3} ( x ^{3} ) ^{3}}{3 ^{3}}

(x^{3})^{3} : x^{9}

= \frac{2 ^{3} x ^{9}}{3 ^{3}}

Fasse zusammen

= \frac{8 x ^{9}}{27}

e x p an d \frac{1}{s ( s ^{2} + 3 s + 5 )}

e x p an d \frac{x ^{2} ( - 10 x ^{3} + 3 x ^{2} - 60 x )}{20}

\frac{d}{d x} ((z) (x^{2} + y^{2} - 2 z^{2} + 12 x - 8 z - 4))

e x p an d e^{2 (x + 1 - l n ∣ x + 1 ∣)}

e x p an d (x^{4} - 2 x^{2} + 2) (x^{2} - 2 x + 3)^{'}