展开 (2,0,-2)y(3,-3,0)

解答

展开

(2, 0, - 2) y (3, - 3, 0)

2 y, 0, 3, - 2 y, 0, 3, 0 - 2 \cdot 3 y, 2 \cdot 3, 0

求解步骤

(2, 0, - 2) y (3, - 3, 0)

= (2 \cdot 0,, - 2) (3, - 3 \cdot 0,) y

乘开

(2, 0, - 2) (3, - 3, 0) : 2, 0, 3, - 2, 0, 3, 0 - 2 \cdot 3, 2 \cdot 3, 0

= y (2, 0, 3, - 2, 0, 3, 0 - 2 \cdot 3, 2 \cdot 3, 0)

乘开

y (2, 0, 3, - 2, 0, 3, 0 - 2 \cdot 3, 2 \cdot 3, 0) : 2 y, 0, 3, - 2 y, 0, 3, 0 - 2 \cdot 3 y, 2 \cdot 3, 0

= 2 y, 0, 3, - 2 y, 0, 3, 0 - 2 \cdot 3 y, 2 \cdot 3, 0

e x p an d \frac{ab ( a ^{4} + b ^{4} )}{a ^{6} + b ^{6}}

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e x p an d \frac{1}{( k + 3 ) ( k + 4 )}

e x p an d (2) (3 x - 2 y = 9)

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