展开-3/((s^2-2s+1)(s^2+4))

解答

展开

- \frac{3}{( s ^{2} - 2 s + 1 ) ( s ^{2} + 4 )}

- \frac{3}{s ^{4} + 5 s ^{2} - 2 s ^{3} - 8 s + 4}

求解步骤

- \frac{3}{( s ^{2} - 2 s + 1 ) ( s ^{2} + 4 )}

乘开

(s^{2} - 2 s + 1) (s^{2} + 4) : s^{4} + 5 s^{2} - 2 s^{3} - 8 s + 4

= - \frac{3}{s ^{4} - 2 s ^{3} + 5 s ^{2} - 8 s + 4}

e x p an d (3 x^{3} - 2 x y + 3)^{4} x

e x p an d, x (x + 1) (x - 4)

e x p an d \frac{3 x}{( x + 1 ) ( x + 2 )}

\frac{d ^{2}}{d x ^{2}} ((y) (2 x^{2} + cos (x)))

e x p an d \frac{8 ( - 3 x ^{2} + 2 )}{( x ^{2} + 2 ) ^{3}}