erweitern 5(e^{(1-0.1x)}+e^{(0.1x-1)})

Lösung

erweitern

5 (e^{(1 - 0.1 x)} + e^{(0.1 x - 1)})

5 e^{1 - 0.1 x} + 5 e^{0.1 x - 1}

Schritte zur Lösung

5 (e^{(1 - 0.1 x)} + e^{(0.1 x - 1)})

Wende das Distributivgesetz an:

a (b + c) = ab + a c

a = 5, b = e^{(1 - 0.1 x)}, c = e^{(0.1 x - 1)}

= 5 e^{(1 - 0.1 x)} + 5 e^{(0.1 x - 1)}

Entferne die Klammern:

(a) = a

= 5 e^{1 - 0.1 x} + 5 e^{0.1 x - 1}

e x p an d - \frac{35 ( - e ^{\frac{1}{x}} - 2 e ^{\frac{1}{x}} x )}{x ^{4}}

e x p an d \frac{31 ( 6.26 s + 77.22 )}{s ^{2} ( s + 143 ) ( 0.155 s + 1 )}

e x p an d \frac{x ^{2} ( - 2 + x )}{6}

e x p an d \frac{1}{3} (13.9 ln (13.9) - 13.9)

e x p an d (x^{2} + y^{2}) \frac{d y}{d x}