vereinfachen 1+(1.6K(x+2)(Tx+1))/(x^2+2x+1.64)

Lösung

vereinfachen

1 + \frac{1.6 K ( x + 2 ) ( T x + 1 )}{x ^{2} + 2 x + 1.64}

\frac{x ^{2} + 2 x + 1.64 + 1.6 K x ^{2} T + 1.6 K x + 3.2 K x T + 3.2 K}{x ^{2} + 2 x + 1.64}

Schritte zur Lösung

1 + \frac{1.6 K ( x + 2 ) ( T x + 1 )}{x ^{2} + 2 x + 1.64}

Wende Bruchregel an:

1 + \frac{b}{c} = \frac{c + b}{c}

= \frac{( x ^{2} + 2 x + 1.64 ) + 1.6 K ( x + 2 ) ( T x + 1 )}{x ^{2} + 2 x + 1.64}

Apply rule:

(a) = a

(x^{2} + 2 x + 1.64) = x^{2} + 2 x + 1.64

= \frac{x ^{2} + 2 x + 1.64 + 1.6 K ( x + 2 ) ( T x + 1 )}{x ^{2} + 2 x + 1.64}

Vereinfache

x^{2} + 2 x + 1.64 + 1.6 K (x + 2) (T x + 1) : x^{2} + 2 x + 1.64 + 1.6 K x^{2} T + 1.6 K x + 3.2 K x T + 3.2 K

= \frac{x ^{2} + 2 x + 1.64 + 1.6 K x ^{2} T + 1.6 K x + 3.2 K x T + 3.2 K}{x ^{2} + 2 x + 1.64}

e x p an d \frac{10 ( s ^{2} + 119 )}{( s + 5 ) ( s ^{2} + 10 s + 169 )}

e x p an d \frac{1}{9} (- 3 e^{- 3 x} x - e^{- 3 x}) + C

e x p an d \frac{10}{s ( s + 4 )}

e x p an d d o m (f + g)

e x p an d \frac{- cos ( a ) ( 1 - cos ( a ) ) + sin ^{2} ( a )}{1 - cos ( a )}